Which one of the following mathematical tools is used for measuring central tendency?
- Mean
- Median
- Mode
- All of the above
Answer: (d) All mean, median and mode are used to measure central tendency.
Which of the following is the best measure of central tendency?
- Mean
- Median
- Mode
- None
Answer: (a) Mean is the best measure of central tendency.
Which one of the following is the best measure of central tendency for quantitative phenomenon?
- Mean
- Median
- Mode
- None
Answer: (a) Mean is the best measure of central tendency for quantitative phenomenon.
Which one of the following is the best measure of central tendency for qualitative phenomenon?
- Mean
- Median
- Mode
- None
Answer: (b) Median is the best measure of central tendency for qualitative phenomenon.
Which one of the following is the best measure of central tendency for the size of shoes?
- Mean
- Median
- Mode
- None
Answer: (c) Mode is the best measure of central tendency for the size of shoes or sandles.
The mean marks of Ram and Shyam in Economics is 80 and 85 respectively. Who is more better student?
- Ram
- Shyam
- Both
- None of them
Answer: (b) The better student is Shyam because his mean marks is more than Ram.
The median marks of Ram and Shyam in Economics is 80 and 85 respectively. Who is more intelligent?
- Ram
- Shyam
- Both
- None of them
Answer: (b) Shyam is more intelligent because intelligence is a qualitative phenomenon and qualitative phenomenon is measured through median. So, the student having more median mark is intelligent.
The variate value that repeats the maximum number of times is called
- Mean
- Median
- Mode
- Range
Answer: (c) Mode is the variable value that repeats the maximum number of times.
The set of data in the value which has highest frequency is called
- Mean
- Median
- Mode
- None of the above
Answer: (c) The set of data in the value which has highest frequency is known as mode.
The distribution of a, b, a, a, a, c, d, e, f is
- Unimodal
- Bimodal
- Multimodal
- None of these
Answer: (a) There is only one mode for this data i.e. a. So, the distribution is unimodal.
The distribution of a, a, b, b, a, b, c, d, e, f is
- Unimodal
- Bimodal
- Multimodal
- None of these
Answer: (b) There are two mode for this data i.e. a and b. So, the distribution is bimodal.
The distribution of a, a, b, b, c, c, a, b, c, d, e, f is
- Unimodal
- Bimodal
- Multimodal
- None of these
Answer: (c) There are three mode for this data i.e. a, b and c. So, the distribution is multimodal.
The empirical relation to find mode is
- 3 Median - 2 Mean
- 3 Median + 2 Mean
- Mean - Median
- Median - Mean
Answer: (a) The empirical relation to find the mode is Mode = 3 Median - 2 Mean.
The mode of the distribution 5, 10, 15, 20, 25 is
- 5
- 10
- 15
- 20
Answer: (c) All the values are repeated only once in the data. So, we calculate mode through empirical relation i.e. Mode = 3 Median - 2 Mean = 3×15-2×15 = 45-30 = 15
If Mean = Median = Mode, the distribution is
- Symmetrical
- Skewed
- Positively Skewed
- Negatively Skewed
Answer: (a) If mean, median and mode of any data are equal, the distribution is symmetrical.
In case of symmetrically distribution of data the condition of mean, median and mode is
- Mean > Median > Mode
- Mean > Median < Mode
- Mean = Median = Mode
- Mean < Median < Mode
Answer: (c) In symmetrical distribution data, Mean = Median = Mode.
If Mean ≠ Median ≠ Mode, the distribution is
- Symmetrical
- Skewed
- Positively Skewed
- Negatively Skewed
Answer: (b) If mean, median and mode of any data are unequal to each other, the distribution is skewed.
If Mean > Median > Mode, the distribution is
- Symmetrical
- Skewed
- Positively Skewed
- Negatively Skewed
Answer: (c) If Mean > Median > Mode, the distribution is positively skewed.
If frequency distribution is positively skewed, then [CMAT 2009]
- Mean < Mode
- Mean < Median < Mode
- Mean > Mode
- Mean > Median > Mode
Answer: (d) If frequency distribution is positively skewed, then Mean > Median > Mode.
If Mean < Median < Mode, the distribution is
- Symmetrical
- Skewed
- Positively Skewed
- Negatively Skewed
Answer: (d) If Mean < Median < Mode, the distribution is negatively skewed.
The ogive is
- Cumulative frequency curve
- Frequency curve
- Relation between mean and median
- Lorenz curve
Answer: (a) The ogive is cumulative frequency curve.
Which one of is the best measure of dispersion? [CMAT 2018]
- Range
- Mean Deviation
- Quartile Deviation
- Standard Deviation
Answer: (d) Standard deviation is the best measure of dispersion.
Which measure of dispersion is suitable for calculation of open and end classes?
- Mean deviation
- Quartile deviation
- Standard deviation
- Lorenz curve
Answer: (b) Quartile deviation is suitable for calculation of open and end classes.
The most commonly used measure of dispersion is
- Range
- Standard Deviation
- Coefficient of Variance
- Quartile Deviation
Answer: (b) Standard deviation is the most commonly used measure of dispersion.
The range of the distribution 5, 10, 15, 20, 25 is
- 5
- 10
- 15
- 20
Answer: (d) Range = L-S = 25-5 = 20
The coefficient of range of the distribution 5, 10, 15, 20, 25 is
- 1/3
- 2/3
- 5/3
- 5/11
Answer: (b) Coefficient of Range = L-S/L+S = 25-5/25+5 = 20/30 = 2/3
The quartiles divide the data of ascending or descending order into
- Eight equal parts
- Three equal parts
- Four equal parts
- Six equal parts
Answer: (c) The quartiles divide the data of ascending or descending order into four equal parts.
Median can also be called
- First quartiles
- Second quartiles
- Third quartiles
- Fourth quartiles
Answer: (b) Median can also be called second quartiles.
If the upper quartile is 20 and lower quartile is 10. Then find inter-quartile range.
- 5
- 10
- 15
- 20
Answer: (b) Inter-quartile range = Upper quartile - Lower quartile = 20-10 = 10
If the upper quartile is 20 and lower quartile is 10. Then find quartile deviation or semi-inter quartile range.
- 5
- 10
- 15
- 20
Answer: (a) Semi-inter quartile range or Quartile Deviation = (Upper quartile - Lower quartile)/2 = (20-10)/2 = 10/2 = 5
Find the coefficient of quartile deviation if upper quartile is 20 and lower quartile is 10.
- 1/3
- 1/4
- 1/5
- 1/6
Answer: (a) Coefficient of quartile deviation = (Q3-Q1)/(Q3+Q1) = (20-10)/(20+10) = 10/30 = 1/3
If the SD is 4, what is the variance?
- 2
- 4
- 8
- 16
Answer: (d) Variance = (SD)² = (4)² = 16
If SD is 4 and Mean is 2. Find the coefficient of SD.
- 1
- 2
- 3
- 4
Answer: (b) Coefficient of SD = SD/Mean = 4/2 = 2
Find coefficient of variation if SD is 4 and Mean is 2.
- 100%
- 200%
- 300%
- 400%
Answer: (b) Coefficient of variation = SD/Mean × 100% = 4/2 × 100% = 200%
The coefficient of variation of marks of A and B student is 35% and 40% respectively, who is more consistent?
- A
- B
- Both of them
- None of them
Answer: (a) If coefficient of variation is less then it is more consistent, more homogeneous, more equitable, more representative. So, A is more consistent.
There are 5 numbers in a data series, first number of the data series is 14 and mean, median and mode are 10, 9 and 6 respectively. Find the 5 numbers. [CMAT 2014]
- 14, 6, 9, 6, 15
- 14, 9, 9, 9, 9
- 14, 9, 10, 8, 9
- 14, 9, 9, 6, 12
Answer: (a) We will check through option in this question. The mode of option a is 6 and the mode of option b, c, d is 9. But question says, mode of data series is 6. So, option a is correct.
In the first 10 overs of cricket game, the run rate was only 3.2. What should be the run rate in the remaining 40 overs to reach the target of 282 runs? [CMAT 2014]
- 6.25
- 6.5
- 6.75
- 7
Answer: (a)
Here,
Score in first 10 overs = 3.2×10 = 32
Remaining score = 282-32 = 250
Required run rate = 250/40 = 6.25
The exam scores of all 500 students were recorded and it was determined that these scores were normally distributed. If Jane's score is 0.8 standard deviation above the mean, then how many, to the nearest until, the students scored above Jane? [CMAT 2014]
- 106
- 250
- 394
- 400